$\left(2x+3\right)^2\left(2x+1\right)^2$

$log\left[\frac{x\left(x+6\right)}{\left(x+3\right)^8}\right]$

$\frac{1-\cos^2\left(x\right)}{\tan\left(x\right)}$

$\left(\sqrt[2]{x}+2x\right)^4$

$\lim_{x\to\infty}\left(\sqrt{4x^2-2x}-3x\right)$

$-11\:x\:\left(+6\right)$

$\int\frac{1}{16x^2-9}dx$