Exercise
$\left(x+3\right)^2+\left(y-5\right)^2=25$
Step-by-step Solution
Learn how to solve problems step by step online. Solve the equation (x+3)^2+(y-5)^2=25. We need to isolate the dependent variable y, we can do that by simultaneously subtracting \left(x+3\right)^2 from both sides of the equation. Removing the variable's exponent. Cancel exponents 2 and 1. Expand the expression \left(x+3\right)^2 using the square of a binomial: (a+b)^2=a^2+2ab+b^2.
Solve the equation (x+3)^2+(y-5)^2=25
Final answer to the exercise
$y=5+\sqrt{16-x^{2}-6x},\:y=5-\sqrt{16-x^{2}-6x}$