$\lim_{x\to4}\left(\frac{x^3+8x}{3x}\right)$
$-20>4-4x$
$\left(xy^7-x^3y\right)\left(xy^7+x^3+y\right)$
$\int\frac{\sqrt{9x^{2}+1}}{3x}dx$
$\frac{dy}{dx}=\tan\left(x\right)=y$
$\left(2x-8y+3z\right)^2$
$\lim_{x\to\infty}\left(\frac{3x-3}{6x^2+5x+6}\right)$
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