$\left(2x+5\right)\left(2x-5\right)=11$
$\frac{\left(-60\right)}{10}$
$790.678+154.987-896.876$
$\left(-12\right)\cdot3+\frac{18}{\left(-\frac{12}{6+8}\right)}$
$3.77\cdot1.125$
$x^3+2y\frac{dy}{dx}=0$
$13\:-\:24\left(11\right)$
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