$\int^2\:3x^2dx$
$x^2+20x-18=3$
$( r ^ { 4 } ) ^ { 6 }$
$\left(3\cdot\tan^2x-1\right)\left(\tan\left(x\right)-1\right)=0$
$\mathrm{\int\left(\frac{5x^3+3x^2+7x-3}{\left(x^2+1\right)^3}\right)\:}\:dx$
$20x^2+6x^2$
$\left(x=y\right)\left(x-y\right)$
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