$6x^3.2x^4$
$x^2+6ax+9a^2$
$\frac{dx}{dt}=x\left(2-x\right)^2$
$\left(x-2\right)\left(3x-9\right)$
$3x+4y=0$
$\:-\:2\:x\:\le\:6\:$
$-3\left(-2^2\right)$
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