$\lim_{x\to\infty}\left(\frac{2x^2+3}{5x^3+4}\right)$
$\left(12^0\right)^3$
$x^2-14x\le-49$
$\frac{2}{x}\le1$
$\frac{5x}{x^{-5}}$
$\lim_{x\to0}\left(\frac{\sin\left(tan\left(x\right)\right)-tan\left(sin\left(x\right)\right)}{x^7}\right)$
$x^8+y^7=2$
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