$\lim_{x\to-\infty}\left(\frac{5x}{\sqrt{8x^2+3}}\right)$
$1-4\sin^2\left(x\right)+4\sin^2\left(x\right)=\sin\left(2x\right)^2-1$
$49a^2-16b^2$
$13x+3\cdot11x-4$
$\frac{x^4}{x}$
$\left(-824\right)-\left(-126\right)$
$20x^2+20x^2-10xf^2$
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