$\frac{x^4+2}{x^2+2x+5}$
$-12\cdot3+18$
$16+4a+a^2$
$\frac{x^3-4}{x^2}$
$-\frac{1}{2}\pi$
$\lim_{x\to0}\left(\frac{x^2-25}{x^2-4x-5}\right)$
$\frac{8\sin\left(x\right)\cos\left(x\right)}{\sin\left(4x\right)+2\sin\left(2x\right)}=\sec\left(x\right)^2$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!