$\frac{x}{5a^4b^{4\:}}^5+c=\frac{x}{5ab}^5+c$
$\left(3x+3\right).\left(2x+2\right)$
$2h+j+3h+4j$
$7x+x-6x$
$\left(18x+5\right)\left(18x-5\right)$
$5cos2x=2$
$\lim_{x\to\infty}\left(\frac{ln\left(2x\right)}{\tan\left(x\right)}\right)$
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