$\left(x+1\right)^2\left(x-3\right)^2-2x^2+4x$
$\sqrt{2.02}$
$100=d+70m^2+4d-3m^2-y^2+25m^2$
$\lim_{x\to0}e^x$
$\frac{x}{x^2+1}dx=\frac{x^2+1}{y+1}dy$
$\frac{d}{dx}\left(6x^2-3xy+y^2=3x+y\right)$
$\frac{dy}{dt}=7$
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