$7x-4<0$
$\left(-3s^2t^3\right)^3$
$5\int\left(2\sin x\right)dx$
$\left(\frac{\pi}{6}\right)+\left(\frac{\pi}{10}\right)+\left(0\right)$
$\:\frac{dy}{dx}=\frac{\left(-3\cdot\:\sqrt{y-19}\right)}{100}$
$7\cdot i^2+144$
$2x^2+x+1=x^2-3x-3$
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