$\frac{sin^4x-sin^2x}{sec\:x}$
$\lim_{x\to\infty}\left(\frac{9e^{\sqrt{\ln\left(x\right)}}}{\sqrt{x}}\right)$
$-6x+9\ge x+9$
$\left(64y^6+x^2+16xy^3\right)^3$
$-10\:+\:9n\:-3$
$\left(5x+3\right)\cdot\frac{x}{2}$
$\frac{1}{3}x^3-x^2+x$
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