$\int\sqrt{3136-64x^2}dx$
$cot\theta\:+1=0$
$\frac{3x+1}{x^2+2x+1}$
$2\left(x+3\right)^2$
$\frac{1}{1-\sec\left(x\right)}-\frac{1}{1+\sec\left(x\right)}$
$\int\left(\frac{e^{6x}}{1+\left(e^{6x}+2\right)^2}\right)dt$
$\frac{dy}{dx}=\frac{x+3}{x-3}$
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