∫1+cos(x)21+cos(2x)dx\int\frac{1+\cos\left(x\right)^2}{1+\cos\left(2x\right)}dx∫1+cos(2x)1+cos(x)2dx
2x2−7x−9=02x^2-7x-9=02x2−7x−9=0
y2−9y2-9y2−9
36n2−66n+12136n^2-66n+12136n2−66n+121
x−6y12⋅2y92y−9\frac{x^{-6}y^{12}\cdot2y^9}{2y^{-9}}2y−9x−6y12⋅2y9
25x2−10x2+2x25x^2-10x^2+2x25x2−10x2+2x
11−(−19)11-\left(-19\right)11−(−19)
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