$\frac{dy}{dx}=y^2-9$
$\frac{dy}{dx}=y^2-4$
$\frac{dy}{dx}=y-y^2$
$\frac{dy}{dx}=y\left(y+2\right)$
$\frac{dy}{dx}=\left(1+e^{-x}\right)\left(y^2-1\right)$
$\frac{dy}{dx}=\frac{x}{2x-y}$
$\frac{dy}{dx}=\frac{x+3y}{x-y}$
The power of a product of factors is equal to the product of each factor to the same power: $\left(b\cdot c\right)^n=b^n\cdot c^n$.
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