∫240 t3+2t2−15tdt\int\frac{240\:}{t^3+2t^2-15t}dt∫t3+2t2−15t240dt
−x−3x+9-\frac{x-3}{x+9}−x+9x−3
16x−12−24x+416x-12-24x+416x−12−24x+4
(8p4−2q)2\left(8p^4-2q\right)^2(8p4−2q)2
∫032(1x−4)dx\int_0^{\frac{3}{2}}\left(\frac{1}{x-4}\right)dx∫023(x−41)dx
−(18). (32) + (−6)-\left(18\right).\:\left(32\right)\:+\:\left(-6\right)−(18).(32)+(−6)
∣−9∣+∣−12∣+(−15)\left|-9\right|+\left|-12\right|+\left(-15\right)∣−9∣+∣−12∣+(−15)
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