$\int4\sqrt[5]{x^3}dx$

$\int-6x\:dx$

$\lim_{x\to\frac{2}{3}}\left(\frac{6x-4}{3x^2+4x-4}\right)+\left(\frac{1}{3x+2}\right)$

$\int\frac{3tan\theta\:\:-4cos^2\theta\:\:\:}{cos\theta\:}d\theta\:$

$2-0.4$

$y^3=\sqrt{9x^2+4}$

$\frac{dy}{dx}=\left(\cos\left(2x\right)\right)$