$-5=-\sec\left(x\right)^2-6-2\sec\left(x\right)$
$6-\left(-3\right)^4$
$x^2-12x+24=0$
$\lim_{x\to-3}\left(\frac{2x^2+2x-12}{x+3}\right)$
$3^{3-1}$
$\left(1+x^2\right)y'\:=\:1+y^2$
$a^2-19a+100$
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