$\int\left(3x^2-4\right)\left(2x^3-8x^5\right)dx$
$f\left(x\right)=\left(2x-2\right)^2$
$\frac{d}{dx}\left(9x^3-y^2-8=0\right)$
$2x^2+3xy-4x$
$+4x\left(-3x+6\right)$
$\frac{-7x+6x^2-19x}{-5+2x}$
$\lim_{x\to0}\:\left(2x-1\right)$
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