$5x^{2}+4x^{2}-y-6y+3$
$\left(9x^2+3x-40\right)\left(9x^2+12x+4\right)$
$-11-19-28$
$-\frac{6}{-2}$
$y=\frac{\sqrt{1-x^2}}{\left(1+x^2\right)^2}$
$\left(3m^2n^3w^5\right)^4$
$\int3a^2x^6dx$
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