$\left(9-2x\right).\left(12-2x\right)$
$4\left(y-6x^2\right)dx+9xdy=0$
$8x+32$
$x^2+2x+7=0$
$y\left(x^2+25\right)=98$
$18+x=27$
$\frac{\left(12y^2\right)}{\left(3y^2\right)}$
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