$\left(32x^{40}y^{-25}\right)^{-\frac{1}{5}}$
$2x^2+3xy-4x$
$\frac{2x^4}{6x}$
$\frac{1+tan^2\left(-\theta\right)}{1-\sin^2\left(-\theta\right)}$
$\int\frac{x^3}{x^2-x+6}dx$
$\left(4x+2x^3\right)\left(4x-2x^3\right)$
$\frac{dy}{dx}=700+y$
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