$\int_2^5\left(x^2\arctan\left(x\right)\right)dx$
$x^4+6x^3-x^2-6x$
$\left(x+\frac{1}{2}\right)\left(x-2\right)$
$2,250\:times5$
$\frac{x^2+3x+2}{-3x^2+19x-6}$
$\lim_{x\to1}\left(\frac{x^2+4x-3}{x^2-1}\right)$
$\lim_{x\to\infty}\left(13xe^{-3x}\right)$
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