$160^1-37$
$\left(\frac{4}{3}-c\right)^3$
$\lim_{x\to1}\log\left(x\right)\log\left(x-1\right)$
$225x^2-360x+144=0$
$3\left(x-2\right)+5=4\left(x-1\right)$
$\frac{x^2+6x+12}{x+2}<\:1$
$x^2-6x=86$
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