$\int\left(3-6x\right)^5dx$
$b^2-8b+15$
$\left(4x^2+5\right)^3\left(16x^4-20x^2+25\right)$
$\frac{sec\:b}{tan\:b+cot\:b}=sin\:b$
$\int x^{20}dx$
$\frac{1}{9}^{-3}\cdot\frac{4}{5}^1$
$cot^2x=\sqrt{3}cotx$
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