$6\sqrt{2x}\cdot4\sqrt[3]{3x^2y}$
$\left(3a^2b-\frac{8}{7}\right)^3$
$\frac{3x-6>2}{x}$
$3x+11\le6x+3$
$6\::\:3\:+\:15\::\:5\:+\:63\::\:7\:$
$\frac{1}{1-cot\left(x\right)}=\frac{sin\left(x\right)}{sin\left(x\right)-cos\left(x\right)}$
$\left(3m+4w\right)\left(3m-4w\right)$
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