$3x+2\left(x+1\right)$
$\sqrt[5]{\frac{x^2}{y^3}}$
$c\left(2\right)+5c-25$
$-4x\:+-6=2$
$2x+9x+20$
$4x-16=2x+2$
$12x^2\:y-16\:x$
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