$x\left(x+8\right)=0$
$x-7<-9x+13$
$\frac{x-30}{\left(x-5\right)\left(x+6\right)}$
$4x^{2\:}5+8x^{2\:\:}3$
$y'=y+y\:^2$
$\left(3x^2h\right)\left(2xh\right)$
$\frac{\left(2x^3z^2\right)^2}{x^3\cdot x^{-4}}$
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