$\left(5x-2y+4m\right)^2$

$3\left(1+2x\right)+\left(3-x\right)+4\left(x+1\right)-1$

$\int\frac{x^2}{\sqrt{441-x^2}}dx$

$\frac{100q^2-4998q+50}{q^2-50+1}$

$\frac{\tan x\sin x}{\sec x-1}=1+\cos x$

$4x+3\le15$

$\tan\left(x+y\right)=\frac{\tan\left(x\right)+\tan\left(y\right)}{1-\tan\left(x\right)\cdot\tan\left(y\right)}$