∫(x3+3x+1x)dx\int\left(\frac{x^3+3x+1}{\sqrt{x}}\right)dx∫(xx3+3x+1)dx
−9x2y−8x2y-9x^2y-8x^2y−9x2y−8x2y
6x5−4x3+3x2+42x2−1\frac{6x^5-4x^3+3x^2+4}{2x^2-1}2x2−16x5−4x3+3x2+4
−13−2(3b+4)=3(b+2)-13-2\left(3b+4\right)=3\left(b+2\right)−13−2(3b+4)=3(b+2)
2x3−3xx2−1\frac{2x^3-3x}{x^2-1}x2−12x3−3x
9z4+30z2+259z^4+30z^2+259z4+30z2+25
x3+y3−z3+(x⋅y+y⋅z+z⋅x)⋅(x+y+z)−x⋅y⋅zx^3+y^3-z^3+\left(x\cdot y+y\cdot z+z\cdot x\right)\cdot\left(x+y+z\right)-x\cdot y\cdot zx3+y3−z3+(x⋅y+y⋅z+z⋅x)⋅(x+y+z)−x⋅y⋅z
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