$\left(\cos\left(x\right)-1\right)^2$
$\left(\left(2^2\right)\right)^4$
$\sqrt[3]{8}\cdot\sqrt[3]{27}^3\cdot4^3$
$\left(3x^2+2x\right)\left(x-4\right)$
$-4\left(x-3\right)+28x$
$\frac{m^{\frac{2}{3}}n^3}{m^{-6}n^{-8}}$
$\frac{x}{1-x}\le4$
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