$$\int\left(-48x^3\sin\left(4x^4+5\right)\right)dx$$

$$2x^2-6x-5$$

$$\frac{\left(-8\right)^{-2}}{3^{-2}}$$

$$\left(x-4t\right)^2$$

$$3c-14=19$$

$$^{\left[8-\left(+4-8\right)+6-2\right]}$$

$$\tan^2\left(x\right)=\frac{3}{8}$$