$\left(4-2m\right)^4$
$5^4.4^4$
$2x\:\frac{2}{2^4}$
$\log\left(x-2\right)+\log\left(x+1\right)=\log\left(40\right)$
$\left(m^2n^3+m^3n^2\right)^2$
$\csc x=\frac{5}{4}$
$-7\left(x-0\right)\left(x-1\right)$
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