$\lim_{x\to\frac{\pi}{2}}\left(4\cos\left(3x\right)\sec\left(5x\right)\right)$
$cosx=-\frac{\sqrt{2}}{7}$
$-214-5-10+30+40$
$\left(m^3+3\right)\left(m^3-7\right)$
$x^2+5x-5=0$
$-\frac{2x^3}{3}+\frac{5x^3}{3}+\frac{x^3}{3}$
$2x<-4$
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