$$\int\left(x^3+3\right)^83x^2\:dx$$

$$\frac{dy}{dx}=\frac{\left(4y+3\right)^2}{\left(2x+5\right)^2}$$

$$\left(e^{-y}-4x\right)dx+\left(3y^2-xe^{-y}\right)dy=0$$

$$\frac{dy}{dx}=\frac{y+3}{1-y}$$

$$6\cdot285$$

$$\left(x^3+5y+3\right)^2$$

$$\frac{dy}{dx}=\left(x^2+c\right)^2$$