$f\left(x\right)=\frac{6}{\left(x^2-5\right)\left(x^2+1\right)}$
$r^2-12r+41=0$
$\int_{-\infty}^oe^2\cos\left(x\right)dx$
$216-\frac{120}{-6}$
$2\left(2x-4\right)+3x=-1$
$\int\left(3x^2\cdot\cos\left(4x^3+9\right)\right)dx$
$\int2sen\left(x\right)\cos\left(2x\right)dx$
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