$\int\frac{x^2-4x+3}{x^2-2x+1}dx$
$\frac{\cot\left(4x\right)}{\cot\left(3x\right)}$
$8=w+1$
$-7+-4+-1+2$
$\left(1\:2\:1\:-1\:\right)$
$d=3.k^2.r.n$
$\left(3^2\cdot6^6\right)^{-3}$
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