(2)(2)3(2)−2\left(2\right)\left(2\right)^3\left(2\right)^{-2}(2)(2)3(2)−2
sec(x)−2sin(x)=(sin(x)−cos(x))2cos(x)\sec\left(x\right)-2\sin\left(x\right)=\frac{\left(\sin\left(x\right)-\cos\left(x\right)\right)^2}{\cos\left(x\right)}sec(x)−2sin(x)=cos(x)(sin(x)−cos(x))2
3t−153≤−1593t-153\le-1593t−153≤−159
x−12≤3 x −1 \frac{x-1}{2}\le3\:x\:-1\:2x−1≤3x−1
∫ 2x(x2+5)7dx\int\:2x\left(x^2+5\right)^7dx∫2x(x2+5)7dx
3n2−8y+15+33n^2-8y+15+33n2−8y+15+3
m2−10m+21m^2-10m+21m2−10m+21
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