Simplifying
$\frac{2}{x^2-1}=\frac{1}{x-1}+\frac{1}{x+1}$
$-24-230-45$
$\lim_{x\to\frac{1}{2}}\left(\frac{6x^2-x-1}{4x^2-4x-3}\right)$
$\frac{a^2-f^2}{a^2}$
$\lim_{x\to0}\frac{-2\left(1-\cos\left(x\right)\right)}{x^2}$
$-1-\left(-3\right):3$
$\int\:\frac{x^2}{x^4-2x^2-8}\:dx$
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