$5x\le2x+1$
$28+x>100\:$
$\left(x+n\right)^6$
$a=\left(x+3\right)\left(x-3\right)-x^2-12$
$\lim_{x\to\infty}\left(\frac{x+\ln\left(4\right)}{x-\ln\left(4\right)}\right)$
$\lim_{m\to4}\left(\frac{m^2-m-12}{x-4}\right)$
$3m+7>28$
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