$\frac{x^6+5x^4+3x^2-2x}{x^2-1+3}$
$\frac{x+3}{-4}=\frac{x-5}{4}$
$\frac{dy}{dx}=\left(x^2-4\right)^5$
$\frac{\left(x^3\right)}{a^9-x^9}$
$\left(4x^8\right)^{-4}$
$\lim_{x\to\infty}\frac{\sqrt{x\:^2-3}}{\sqrt[3]{x^3+1}}$
$\left(\frac{5}{4}a^2-\frac{5}{4}n\right)^2$
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