$\left(\frac{1}{3}x+\frac{1}{2}\right)\left(\frac{1}{3}x-\frac{1}{2}\right)$
$\left(m-3\right)\left(m+5\right)$
$\frac{x}{9}+64=100$
$f\left(x\right)=ln\left(\frac{e^{2x}}{cosx}\right)$
$b\left(x+1\right)+6\left(x+2\right)=7\left(x+3\right)$
$\frac{2}{x+2}-\frac{1}{3x-1}$
$\left(\frac{1}{7}m-4\right)\left(\frac{1}{7}m+4\right)$
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