$\left(\frac{6}{2}\right)^2$

$\int\left(\frac{2t+2}{\left(t^2+1\right)\left(t-1\right)^3}\right)dt$

$\int\frac{\sin^4\left(\ln\left(x\right)\right)}{x}dx$

$6\:+\:2x\:\:\ge\:\:x\:-\:3$

$-5x+4<3$

$\lim_{h\to0}\left(\frac{e^h-e^{-h}}{\sin\left(h\right)}\right)$

$x+15=51$