$x^5-4x^4+4x^3$
$\left(17ab\right)\left(-4b^2\right)$
$4r-2r+5$
$5\left(x+1\right)-4\left(x-1\right)$
$-5\cdot\left(-38+2\cdot\left(-24+47\right)\right)+2$
$xln\:x\:dy-ydx\:=0$
$\int\left(x^4\cdot sin\left(3x^5\right)\right)dx$
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