$\lim_{x\to-\infty}\left(\frac{\left(2-x^3\right)}{\left(x^2+x\right)}\right)^3$
$4x^2-160x+1600=900$
$\frac{dy}{dx}=\frac{\left(xy-y-3+3x\right)}{\left(4y-2x-8+xy\right)}$
$43\cdot57$
$fa+x^2+3x+9^2$
$f\left(x\right)=\frac{9}{x^2-5x-14}$
$-12m+36m-36m-42m$
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