$36\left(-25+7\right)-4\cdot\left(-10+8\right)$
$\left(3a^3\right)+4b^4\left(3a^3-4b^4\right)$
$\frac{\left(6a+5+a^4-12a^3\right)}{\left(-3+a^2\right)}$
$\frac{6}{4-x}\:,\:c=1$
$5b+7b$
$\lim_{x\to0}\left(\frac{\left(2x+1\right)}{\left(2x\right)}\right)^{5x}$
$\:1+2cos2x=\:3cos2x\:-sin2x\:$
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