$tan^2\left(x\right)+sec^2\left(x\right)=sec^4\left(x\right)-tan^4\left(x\right)$
$\int\left(-12x\:-1\:\right)\sqrt[2]{-6x^2-x+1}dx$
$\frac{d^8}{dx^8}\left(3x-2\right)^8$
$\left(t-0.5\right)\left(t^2+0.5t+0.25\right)$
$4\cdot3-2y$
$-3-2-4-1-7-10$
$-10\:=\:x\:-\:21$
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