$x^3\sqrt{x}^4-1$
$x=-4x^2+12x-9$
$6x^2y^3\left(xy\right)$
$\left(x+\frac{3}{4}y\right)\left(x-\frac{3}{4}y\right)$
$\left(6y+7\right)^2$
$9x^{2-48x+64}$
$250x^2-40$
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