$2xy\frac{dx}{dy}=1+y^2$
$\int2x\sqrt{2-3x}dx$
$\frac{dy}{dx}=\frac{18y^3}{\left(1-3x\right)^2}$
$3ax+3x+4y+4ay$
$4\cdot5^3-2\cdot\left(-3^2\right)-5\cdot\left(-1^4\right)-3$
$\left(x+y\right)\left(y\:+\sqrt{x}\right)$
$dy=x^4y^2dx$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!